no - not at all. I can not find that it is outside any voltage limits nor timing limits.
Indeed such a pulse could be a benefit for a crystal to start up. Some kind of kick start.
Klaus
added:
Don´t get me wrong: I don´t like those guessing games. Several times now I asked for more detail informations. In future I will only respond if there is enough useful information.
How much energy do you think was absorbed by the Xtal with that pulse? What is the Spectral Density at the resonant frequency of that pulse vs. a step pulse? Do you know how the Pierce Xtal Oscillator works inside a uC?
"Measurement of crystals also requires drive level to be specified. For better accuracy, lower drive levels are preferred.
Drive levels are typically between 10uW to 2mW.
Lower-frequency devices with larger quartz wafers can handle higher drive levels without damage.
Smaller, higher frequency devices may be damaged by high drive levels, above 5mW.
Today’s applications rarely drive acrystal higher than 2mW with typical levels at 100uW maximum.
CTS will specify a standard maximum drive level at 100uW, if not defined by a customer.
Since the drive level indicates power consumption by the crystal unit while the oscillation circuit works, it is important to keep the crystal within drive level specifications"
A crystal oscillator is an electronic oscillator circuit that uses a piezoelectric crystal as a frequency-selective element. The oscillator frequency is often u...
just look at the full schematic of an oscillator.
It usually consists of
* inverter
* XTAL
* two cpacitors
Now the situation shows "power up".
At power up both capacitors are considered discharged => 0V
one of these capacitors is at the input of the inverter.
Now the input of the inverter (at power up) is 0V. So what output of the inverter do you expect?
I expect HIGH.
and due to this HIGH ... you get a delayed but rising signal through the XTAL (maybe there is an additional R across the XTAL to ensure proper start up)
inverter output (HIGH) --> C --> XTAL --> C --> inverter input
So the inverter gets a rising signal at the input
and due to this ... I expect the inverter output to fall
I think this is quite expectable. And can be seen in any simulation
I recommend to do such simple simulations on your own. (Mind to switch OFF steady state calculation)
Simulators are easy to use and free, so no excuse not to use them.
(Indeed I´m not a friend of simulators, because the can only calculate as precise as the inputs are. Thus the simple ones don´t care about GND_bounce and PCB layout influence.
But for teaching / learning simple circuit behaviour they are quite useful. No risk for explosions, smoke, smell .. while you can see almost every detail in voltage and current for each single device)
All uC ports for ext. osc. have an input and output with an ext. cap to ground on input and an inverter and parallel Megohm for dc self-bias. Thus the input starts at 0 and output pulse to 1 pulling up the input which causes output to sag to 0 until the RC self bias reaches Vdd/2 or whatever the actual threshold is to start oscillating.