Could you please solve this for y

[verda]

2(dy/dx)=ytanx

 

[gepla]

2(dy/dx)=y.tanx
∫2dy/y = ∫tanx.dx
2ln|y| = - ln|cosx| + C

ln(y²) = -ln|cosx| +lnc1


ln(y²) = ln(c1/|cosx|)
y² = c1/|cosx|

y = ±√(c1/|cosx|) with cosx≠0 and c1>0