Hi,
Just a small clarification, my input to the non-inverting terminal of the op-amp is between 0-2V. So, since it's a voltage follower, the output of the op-amp will also swing between 0-2V right?
The datsheet does not know about your application, nor do we.
In post#1 one can not estimate/calculate your expected output voltage
In post#2 you talk about a voltage follower (now we know you want gain =1) and an inputt voltage of 5V (not 0-2V).
I´m confused.
But to answer your question: Yes, on a voltage follower with input of 0..2V the output ideally also is 0..2V
Now, why do we need to think about the output swing values in the table that has values around 5V?
Because in post#3 you wrote so.
Also, just a clarification, how to calculate the maximum normal current that the op-amp can deliver when the output (actually following the input) is between 0-2V? Can you tell how to make an approximate safe calculations for normal conditions?
Lets´s try again: It depends on your load and how it is connected.
All use ideal OPAMP in voltage follower configureation, all with max current of 100mA:
1) load connected to 0V: Load resistance is 20 Ohms. Max power dissipation on OPAMP: 3V x 100mA = 300mW (easiest condition for driving voltage 0..2V)
2) load connected to 1V: load resistance 10 Ohms. Max power dissipation 3V x 100mA = 300mW
3) load connected to 2V: load resistance 20 Ohms. Max power dissipation: 2V x 100mA = 200mW
4) load connected to 5V: load resistance 50 Ohms. Max power dissipation: 2V x 60mA = 120mW
To get a more precise answer, you need to give use the "load conditions" first.
BTW: why don´t you use a simulation tool? Then you can play around, measure every value you like....
They are free and easy to use...
Klaus