What do you think about the next current source? It has to drive a current, in RL, of 0.1 [A] the most exactly it can be. For that, I put a transitor which has a Vbe= Ic * 6.8Ω ; so if the current of 0.1 [A] goes up, the transistor drives and the currents goes down.
The hfe of the transistor are 256.
I do not know if I must put an Rc in the Q2
PD: I saw the other topic of the constant current source and I think this topic are different
That current in that circuit will vary about 0.3% per degree C change in temperature due to the Vbe voltage variation of Q2 with temperature.
Is that acceptable?
P.S. What's the purpose of R1? That will reduce the accuracy (feedback gain) of the circuit.
the purpose of this circuit it's to measure the resistor value of RL which goes from 0.1Ω to 10 Ω, and with a current of 0.1 [A], measuring it whit a voltimeter :bsdetector: , with a value of 10 [mV] there is a resistor of 0.1 [Ω]; a value of 22 [mV] a resistor of 0.22 [Ω], etc . I put the resistor of 47 Ω in emitter because it's reduce the temperature effect with temperature. But I want to reduce it more, so I use the transistor Q2.
Do you think it's so necesary the Q2? I put it because the teacher said that I have to be a good source and it has to be a better thing that just one transistor in emitter commun mode. So, I thought to put Q2 :razz:
This would be the final circuit.
But I do not know what value must be R2. Because I do not know what value would have Ic2 (Q2).
Let's say you put R1 into the drain branch of Q1, as suggested (and better). R2=0 . At current limit, base of Q2 resp. collector of Q1 will be at ≈ 2*0.65 = 1.3V. At nom. power supply of 9V , there are 7.7V over R3, which drives a current of 0.7mA through R3. Let's say Q1 has B=500 , so it needs 0.2 mA base current for Ic1=100mA, Q2 takes the rest, hence Ic2=0.5mA - neglectable against Ic1.