It's a voltage regulator. It uses negative feedback from the output to adjust the pass transistor to keep the output voltage at the adjusted value, independent of the load current.
To see its operation, assume there is a slight drop in output voltage. Follow that change in voltage through the circuitry to see which voltages to up and which go down (ignore the magnitudes), and how that affects the output voltage.
i understand that it is a voltage regulator ..the circuit does not work if you reverse the polarity/swap the pins..question is how exactly do you find out in circuits like this whether it is a positive feedback/negative feedback ? if some one can throw some light on the issue of negative feedback on the positive terminal of the opamp..it would be helpful
The lower transistor (original drawing!) - together with the resistor - operates in common emitter configuration. Thus, there is a phase inversion between its base (opamp output) and the base of the path transistor.
This phase inversion provides negative feedback (and requires a non-inverting opamp).
i understand that it is a voltage regulator ..the circuit does not work if you reverse the polarity/swap the pins..question is how exactly do you find out in circuits like this whether it is a positive feedback/negative feedback ? if some one can throw some light on the issue of negative feedback on the positive terminal of the opamp..it would be helpful
It isn't just the polarity of the op amp, it's the polarity of the signal through the total feedback path. To determine the polarity of the feedback, you just follow the path from output to input and note any polarity inversions in the circuits along the way. If the sum of those inversions is negative, then the feedback is negative. Thus if the op amp is connected with the positive input, but it has an inverting transistor at it's output, then the path through those two devices is inverting.