I still don't know if my calculation is correct and I don't have the same circuit as I do in the simulation. My problem is that I have to dimension the capacitor so that cos (phi1) =0.8.
But I can't set the C anywhere in the simulation.
In your first post, you confirmed that my calculation is correct. Are you still of the same opinion? I am now a little unsure because many posters write otherwise, but without providing a solution or an explanation, unfortunately this is of no use to me.
So my calculation is correct?
Sorry, I didn't examine details of your math. It appears correct for a sine-cosine setup however I used the simulator and it showed me the unexpected. The inductor current-lags-voltage truism does not apply when we alter the sine wave via On-Off switching.
So as an exploratory trip, this simulation has:
* a bit of inductive drop on the AC side,
and
* a bit of choke effect on the DC side.
It uses your specs (as best as adjustments permit).
Sine waves are retained yet current-limited. It does not include On-Off switching.
It has your 186 uF capacitor.
From the look of it power factor is almost aligned.
Perhaps this fulfills your spec 0.8 figure.
At the same time, current draw is reduced from the supply. Benefit of power factor correction with the right value capacitor.
If we speak of an old-school approach I suppose that resembles it. Falstad's simulator taught me almost everything I know about power factor error and correction.
Some people rely overmuch on simulated circuitry. Some people rely overmuch on expected behavior in circuitry. This is a case where the simulator has a surprise in store. Rectifying AC changes everything in your power supply. Inductors yield different behavior with DC versus AC. So the diode-bridge creates a 'wild card' in your power supply.