common mode gain of cmos differential amplifier with current mirror load

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gstekboy

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I know that it is approximately zero. Can anyone help me how it become zero from small signal analysis.
What is the final gain equation from small signal analysis?
 

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Since you have terminated the output with equivalent voltage source, the circuits becomes exactly symmetrical -->so the circuit can be folded into one tail source cascoded with Input pair (2w/l) & the nmos load as diode connected with (2w/L) -->Now caluculating gain from Vcm to output -->we will get gdst/gmn (<<<<1) [gdst-->gds of the tail transistor]
 

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