Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Common drain amplifier/voltage buffer

Status
Not open for further replies.

giri_lp

Member level 3
Member level 3
Joined
Feb 11, 2006
Messages
61
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,286
Activity points
1,657
common drain

Generally it has been mentioned that when high gain amplifier has to drive a low impedance load the usage of voltage buffer ( high i/p impedance and low o/p impedance) is recommended. Please explain me the logic behind this. Why we can not directly connect a high impedance load to a low impedance load??
 

voltage buffer

When there is a low output impedance, the current flowing through the load is high. If this current were to flow through the high gain amplifier, the gain will decrease considerably. Thus, using a buffer stage makes most of the this current flow through it, while simultaneously having control on the gain of your amplifier (by controlling the current flowing through it by proper biasing).
 

    giri_lp

    Points: 2
    Helpful Answer Positive Rating
common drain amplifier

When there is a low output impedance, the current flowing through the load is high.


Sounds a bit confusing.

If this current were to flow through the high gain amplifier, the gain will decrease considerably.


Why ?

Thus, using a buffer stage makes most of the this current flow through it, while simultaneously having control on the gain of your amplifier (by controlling the current flowing through it by proper biasing).

Does somebody understand ?

I´ll try another short answer:
The gain of a stage depends strongly on the effective resistance (working resistance) which the controlled BJT output current flows through.
This resistance consists of three parts in parallel: BJT internal output resistance, resistance in the collector path and the resistance which is connected at the collector node (load). This explains the influence of the load resistance if it is rather low (because in a parallel connection the lowest part dominates).
 

    giri_lp

    Points: 2
    Helpful Answer Positive Rating
Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top