Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Choosing Diode For Energy Harvesting Project

Status
Not open for further replies.

ZenithSoul

Newbie level 2
Newbie level 2
Joined
Sep 21, 2010
Messages
2
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Activity points
1,299
Hi there everyone.
I have this particular project ongoing about harvesting current energy.
I'm using a dynamo rated 12V 25W and I want to connect this to a 12V battery to charge it up.
Thus, i need a diode to prevent the battery from powering the dynamo instead.
Anyone can give me some advice?
 

I don't think it matters very much, the details of the diode.
The difference between a Schottky (~0.3 - 0.4V) and a
plain rectifier (0.7V) in efficiency terms is modest.

Figure you will likely run unregulated and input-torque-
starved at 2A output:

Voutput = Vbat+Vrect
Eff1 = 12/12.3 = 97.6% (Schottky 0.3V)
Eff2 = 12/12.7 = 94.4% (PN 0.7V)

Either of these would seem acceptably good, to me.

I'd suggest a 5-10A, 50PIV rated diode with a tolerably
low high temp leakage (you could figure what is acceptable
from either the required charge retention time, or service
factor charge/discharge and an efficiency allocation).
 
What type of battery is it?

Keith

Hi there. It would be most likely a 7.2aH Lead-Acid Battery.
Using it because of its light weight and portability, as it would only be used for simulating conditions in an exhibition.

---------- Post added at 11:11 ---------- Previous post was at 11:10 ----------

I don't think it matters very much, the details of the diode.
The difference between a Schottky (~0.3 - 0.4V) and a
plain rectifier (0.7V) in efficiency terms is modest.

Figure you will likely run unregulated and input-torque-
starved at 2A output:

Voutput = Vbat+Vrect
Eff1 = 12/12.3 = 97.6% (Schottky 0.3V)
Eff2 = 12/12.7 = 94.4% (PN 0.7V)

Either of these would seem acceptably good, to me.

I'd suggest a 5-10A, 50PIV rated diode with a tolerably
low high temp leakage (you could figure what is acceptable
from either the required charge retention time, or service
factor charge/discharge and an efficiency allocation).

Thanks for the reply. However, I'm not too familiar with the technical jargon used by you and thus, pardon me for the inconvenience caused,
could I get any part no from you in order to purchase the diode? I'm currently in Singapore and the retailers down here are not very helpful with their replies
when i ask them for help. Cheers!
 

Make sure you get enough voltage to charge the battery. Normally you want 13.8V to charge a 12V lead acid battery. You will probably get that from your dynamo - the voltage will change with the load. Otherwise you would need a switching regulator to maintain a constant voltage.

Keith

---------- Post added at 08:49 ---------- Previous post was at 07:31 ----------

Something off this list should do the job:

Your Search Results | Farnell United Kingdom

Keith.
 

tci test connection

it really help out to the new bees as energy harvesting is essential and more important thing is that how to implement the factors.As far as I am concern diode plays an important role in it.
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top