Hello,
I read the following from Wikipedia:
According to Wikipedia
article:
To describe the ideal operation of the circuit, number the diodes D
1, D
2 etc. from left to right and the capacitors C
1, C
2 etc. When the clock Φ1 is low, D
1 will charge C
1 to Vin. When Φ1 goes high the top plate of C
1 is pushed up to 2Vin. D
1 is then turned off and D
2 turned on and C
2 begins to charge to 2Vin. On the next clock cycle Φ1 again goes low and now Φ2 goes high pushing the top plate of C
2 to 3Vin. D
2 switches off and D3 switches on, charging C3 to 3Vin and so on with charge passing up the chain, hence the name charge pump. The final diode-capacitor cell in the cascade is connected to ground rather than a clock phase and hence is not a multiplier; it is a peak detector which merely provides smoothing.[2]
A critical question is that when C
1, with Q=C1Vin, is raised to 2Vin by Φ1, when charging C
2 it will
lose charge and the voltage will drop. The same problem extends to all subsequent chaining steps.
After carefully thinking I still feel it a legit question and don’t see why it is left unexplained. I actually suspect the charging process takes multiple iterations to reach equilibrium: in each iteration the charging capacitor (like C
1) gives some charge to the next one (C
2), and
regains the lost capacity in the next iteration. Several
iteration are needed to final charge output (Vo) to the desired value, but NOT in one iteration.
Could anyone explain this problem?
Matt