Case statement condition problem

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sureshaa

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Hi ,

I want to check the condition in case like below,
case op is
when cond1 => statement;
when cond2 => statement;
when cond3 => statement;
when cond4 => statement;
when others => Null;
end case;

My conditions are within some range. Example 1 to 20, 21 to 40, 41 to 60, 61 to 81.I could not write all the numbers between 1 to 20.Is there any command for checking range in case condition.

Thanks in advance.
Suresh
 

i hope you are using C. first you use "if" statement to assign some fixed value to some variable(say x=1) if your condition is within first range i.e. 1-20. give x2 for condition 21-40 and so on. now u you can easily use switch case statement for x.
this is one of the solution. there can be much easier solution also.
 


The only other option on the conditions is

case op is
when 1 | 2 | 3 => statement;
when 21 | 22 | 23 => statement;
...

But listing 20 items on one line will look a bit messy. The other option would be to compute a variable that already classifies them for you. In your case, if you took 'op' and divided it by 20 and then used the case statement on that new variable like this...

Code: 
op_div20 := op / 20;
case op_div20 is
    when 0 => statement;
    when 1 => statement;
    when 2 => statement;
    when others => null;
end case;

Kevin Jennings
 

Hi ppdr,

Thanks for your reply. I agree. but I need to know whether any syntax (to use within case itself) is there without using any combinational logic condition checking or if checking. To add more clarity,

case count is
when (1|2|3|4|5|6|7|8|9|10|11|12|13|14|15|16|17|18|19|20) => statement;
.
.
.
.
End case;
To replace 1|2|3|......19|20 sequence, is there any statements are there (combinational logic condition checking or if checking) ?
 

but i think Sureshaa want to execute some statement if the number is between range 1-20,21-40 .......
 

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