Oct 16, 2011 #1 moonnightingale Full Member level 6 Joined Sep 17, 2009 Messages 362 Helped 5 Reputation 10 Reaction score 5 Trophy points 1,298 Activity points 3,832 Can u kindly rougly tell me passband regions for these two graphs Attachments passband.gif 19 KB · Views: 135
Oct 16, 2011 #2 D devilwar Member level 2 Joined Aug 18, 2011 Messages 45 Helped 10 Reputation 20 Reaction score 10 Trophy points 1,288 Location Bengaluru, India Activity points 1,544 Cut the largest lobe with a line perpendicular to y-axis at -3db. The two points at which the line cuts the lobe gives you the passband. Fig 1. 1.3 to 1.4(approx) Fig 2. 0.65-0.8(Approx)
Cut the largest lobe with a line perpendicular to y-axis at -3db. The two points at which the line cuts the lobe gives you the passband. Fig 1. 1.3 to 1.4(approx) Fig 2. 0.65-0.8(Approx)
Oct 16, 2011 #3 moonnightingale Full Member level 6 Joined Sep 17, 2009 Messages 362 Helped 5 Reputation 10 Reaction score 5 Trophy points 1,298 Activity points 3,832 Thanks a lot Devilwar Can anybody second him and confirm his answer
Oct 17, 2011 #4 D devilwar Member level 2 Joined Aug 18, 2011 Messages 45 Helped 10 Reputation 20 Reaction score 10 Trophy points 1,288 Location Bengaluru, India Activity points 1,544 Actually the passband is assumed from where power is greater than or equal to half. So voltage/ current becomes 1/root(2). Now 1/root(2) is -3db in log scale. log(10) 2= 0.3010 20 log(10) root(2)=10 log(10) 2= 3.010 almost = 3db
Actually the passband is assumed from where power is greater than or equal to half. So voltage/ current becomes 1/root(2). Now 1/root(2) is -3db in log scale. log(10) 2= 0.3010 20 log(10) root(2)=10 log(10) 2= 3.010 almost = 3db