what do u want to do? is it like a cap and a resistor is connected in series with the base terminal and then connected to the ground. is there some biasing too? like a voltage divider bias?
zahrein, do *you* think it would work? Why, or why not?
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No, you need the DC bias. I think you are confusing the property of voltage and it's rate of change with DC biasing. There is no way around the fact that a signal goes through a capacitor and the bias on the other side is a DC.
i agree with u kevin. but if u have an FET that maybe there would be some "self bias" and maybe the circuit could do something. but the person asking the question was probably referring to BJTs so i think that isnt a possibility. i wonder if such a set up will be of some use in the FET domain :?
If you ground the gate of a FET you get current. With a capacitor there is an open circuit at DC. I think there exists a small amount of gate current to make the FET operate. I don't think there is enough bias with a gate capacitor in the way. An open circuit will cause the gate voltage to equal the source voltage anyway.