Can anybody explain the following opamp circuit working

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k.kumar1044

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Hello ,

Can anybody explain the section wise working of the following opamp circuits.
Specially the capaitance resistance pairs in the begning.
Plz help .

thanking you all in advance.
 

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Referred to the input of the last opamp (without any feedback) the circuit works as an allpass.
This means that for different frequencies the amplitudes remain constant and the phase is shifted as a function of frequency.
This description does not yet include the function of the input bandpass which can be described separately.
 
plz tell me what those capacitance and resitance pair at the start doing.. Is it band pass filter? Thanks
 

its a band pass filter.....with series RC acting as a HIGH PASS and parallel RC acting as LOW PASS....

EA
 
any guess , whats happening in this section .. in terms of addition of current and voltages of different phases..anything will be helpful

Thanks
 

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k.kumar1044 said:
any guess , whats happening in this section .. in terms of addition of current and voltages of different phases..anything will be helpful
Thanks
Click to expand...

`"What's happening in this section" ?

This section summarizes two signals: Vout1+Vout2.

Vout1=Vin*[1/(1+jwRC)] >> first-order lowpass
Vout2=-Vin*[jwRC/(1+jwRC)] >> first order highpass.

To proove that the magnitude of the sum is constant and the phase moves from zero to -180deg. you must evaluate the sum of both output signals separately as magnitude and phase.
The calculation is rather straight forward - however a bit involved.

- - - Updated - - -

Why do you expect a triangle shape at the output?
 
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