Bootstrapping circuit

Suppose we apply 12V to turn On M1. This causes the node labelled 'out' to convey 12V. That has the effect of negating the bias on M1 which makes M1 shut off (entirely or partially). Hence to keep M1 turned on its bias voltage must be a few volts greater than its source voltage.

This creates the need for a bootstrap capacitor. Ideally C1 is switched so it acquires 12V and becomes part of a voltage doubler. This is switched to apply 24V to M1 bias at the proper time turning it On.
 

V1 is a 1 kHz square wave generator. This acts as the input signal that will switch the circuit states.
The square wave provides alternating high and low signals to the circuit, which will control the MOSFETs through the switching mechanism.
SW1 and SW2 are configured in such a way that only one switch is closed at a time.
When SW1 is closed, SW2 is open, and vice versa. This allows the square wave signal to either pass through SW1 or SW2 but not both at the same time.
The switches control which MOSFET (M1 or M2) receives the signal.
 

Similar threads

Cookies are required to use this site. You must accept them to continue using the site. Learn more…