Boolean Algebra help

Status
Not open for further replies.

mr2turbo

Newbie level 3
Joined
Feb 6, 2014
Messages
3
Helped
0
Reputation
0
Reaction score
0
Trophy points
1
Activity points
25
Hi all,

i have recently looked at some simple logic and come up with Q = (A + 'B) . (B + C) . C

It needs simplifying but i am useless at Boolean and i feel i haven't been taught well at all.

Here's what i did:

Q = (A + 'B) . (B + C) . C

Q = A + B . A + C . 'B + B . 'B + C . C

Q = A + B . A + C . B . 'B + C

Q = A + B . A + C . 'B + C

Firstly i don't even know if what i have done is correct. I have just used the laws and rules where i think they apply. Secondly, i know it will simplify even further.

Please can somebody help!

Thanks
 

I think the simplest form possible is as follows:

Q = (A + 'B) . (B + C) . C
Q = (A + 'B) . (B.C + C)
Q = A.B.C + A.C + B.'B.C + 'B.C
Q = A.B.C + A.C + 0 + 'B.C
Q = A.B.C + A.C + 'B.C
Q = C.(A.B + A + 'B)
Q = C.(A.(B + 1) + 'B)
Q = C.(A + 'B)
 

Status
Not open for further replies.
Cookies are required to use this site. You must accept them to continue using the site. Learn more…