Apr 10, 2014 #1 M mr2turbo Newbie level 3 Joined Feb 6, 2014 Messages 3 Helped 0 Reputation 0 Reaction score 0 Trophy points 1 Activity points 25 Hi all, i have recently looked at some simple logic and come up with Q = (A + 'B) . (B + C) . C It needs simplifying but i am useless at Boolean and i feel i haven't been taught well at all. Here's what i did: Q = (A + 'B) . (B + C) . C Q = A + B . A + C . 'B + B . 'B + C . C Q = A + B . A + C . B . 'B + C Q = A + B . A + C . 'B + C Click to expand... Firstly i don't even know if what i have done is correct. I have just used the laws and rules where i think they apply. Secondly, i know it will simplify even further. Please can somebody help! Thanks
Hi all, i have recently looked at some simple logic and come up with Q = (A + 'B) . (B + C) . C It needs simplifying but i am useless at Boolean and i feel i haven't been taught well at all. Here's what i did: Q = (A + 'B) . (B + C) . C Q = A + B . A + C . 'B + B . 'B + C . C Q = A + B . A + C . B . 'B + C Q = A + B . A + C . 'B + C Click to expand... Firstly i don't even know if what i have done is correct. I have just used the laws and rules where i think they apply. Secondly, i know it will simplify even further. Please can somebody help! Thanks
Apr 10, 2014 #2 andre_luis Super Moderator Staff member Joined Nov 7, 2006 Messages 9,644 Helped 1,191 Reputation 2,401 Reaction score 1,219 Trophy points 1,403 Location Brazil Activity points 55,943 I think the simplest form possible is as follows: Q = (A + 'B) . (B + C) . C Q = (A + 'B) . (B.C + C) Q = A.B.C + A.C + B.'B.C + 'B.C Q = A.B.C + A.C + 0 + 'B.C Q = A.B.C + A.C + 'B.C Q = C.(A.B + A + 'B) Q = C.(A.(B + 1) + 'B) Q = C.(A + 'B) Click to expand...
I think the simplest form possible is as follows: Q = (A + 'B) . (B + C) . C Q = (A + 'B) . (B.C + C) Q = A.B.C + A.C + B.'B.C + 'B.C Q = A.B.C + A.C + 0 + 'B.C Q = A.B.C + A.C + 'B.C Q = C.(A.B + A + 'B) Q = C.(A.(B + 1) + 'B) Q = C.(A + 'B) Click to expand...