Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Bohr's Atom Model Questions

Status
Not open for further replies.

Taher_Selim

Member level 5
Member level 5
Joined
Mar 26, 2008
Messages
83
Helped
11
Reputation
22
Reaction score
4
Trophy points
1,298
Location
Egypt
Activity points
1,801
Hello Guys,
I was reviewing Bohr's Atom model. I got the following question that couldn't find answer by me:

All sources that I have reviewed equates centripetal force of the electrons with attractive force. they are using coulomb's law to describe the attractive force. They used the following formula:
F = (e^2)*K/r^2
However an attractive force due to Coulomb's law is:
F = - (e^2)*K/r^2
I mean there is negative sign that is missed in the first formula.
Do you have any explaination for discarding this sign?
 

This means the total energy is negative and inversly proportinal to it's radius,the energy is pulling out the orbiting electron away from the inner shell(proton)for infinite value of 'r'and the energy said to be zero.
 

No! No negative energy!
The sign is related to the sense of the force. Teh sense is a convention.
If you consider that positive force is towards the centre, then the resulting sign is positive, and otherwise it is negative.
Regards

Z
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top