Bode diagram of 1/(s-1)

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lignin

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hello forum.
how can ı find the bode diagram of 1/(jw-1) ?
especially phase diagram is important and ı dont describe phase equation ?
 

@lignin: If you need the Bode Plot of any transfer function quickly,MATLAB would do the trick.
Just need two commands,
Code: 
H = tf([1],[1 -1]);
bode(H)
Attached is image.
If you need to do it manually,just follow basic Bode rules
 

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ı got this plot in matlab but ı cant prove this plot in paper .
 

Ok,you need phase-plot of 1/(s-1) = 1/(jw-1).

The phase-angle for the term 1/(jw -1) = -1/(1-jw) is given by,
-180 + (phase of 1/(1-jw)) = -180 + (-tan^-1(-w)).
As w -> 0 phase = -180 deg.
for large values of w,: -tan^-1(-w) = 90.Total phase = -180 + 90 = - 90 deg.
for w = 1,-tan^-1(-1) = 45 deg..Total phase = -180 + 45 = -135 deg.
 

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