Mrusten
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hi thanks for answerHi,
LEDs need at least 2V to operate .... I can't see that this circuit can satisfy this.
LEDs need a current limit to about 20mA .... I can't see how this can be satisfied.
If some state gets latched ... how is it released?
I don't know how the PLC is involved at all.
There is no clear question.
And since you don't want some recommendations ... I 'm not sure what is allowed to recommend .. or to be asked.
Klaus
thanks for answer but it wil not detect anything before segnifisent voltagedifferense and there is no feedback to plc and latching of the ledBy putting a single led across a good fuse, it stays dark. However a blown fuse automatically subjects the led to system voltage.
View attachment 185391
Yes the voltage across a blown fuse wil be low, thats why the circuit i found is using current to determend the state of the fuse.Hi,
But the problem here is: you have a bus .... and you have batteries.
So if one fuse blows ... the voltage across the battery does not drop the same way as with a resistive load. The battery voltage may drop some 100mV ...
And the same way ... the bus voltage does not rise. So the voltage across the blown fuse may be some 100mV.
idea is the same as mine, to monitor fuses in a paralell bank under any situationI don't know the idea behind the circuit. But maybe it is some energy backup or storage system.
senter is connected to make sure all cells is balanced, a bms is connected to the center pin as wellI don't understand the "center connection" at all. The batteries are never fully combined and never fully separated.
in a small system yes but in my case its a large bank with small loads, purpose of the bank is to provide electricity several days, when drawing max inverter capacity the current is 22A from each cell, typical use of the inverter is 10 - 20% so the other fuses could trip but its not likely in normal operation of the systemIt's very likely that when one fuse in one row (top or bottom) trips ... the other fuse in the same row will follow to trip, because the total current is then taken by the remaining (fewer) paths ... which means the current in each remaining path will rise -> overcurrent --> fuse trip. Avalanche like. Total system fail.
all modules is from used cars, sertanly not new so its again a posibility for that to happen but not likely, the leaf modules can provide 500A and im using 25 at apsolutely max eaven if a cell is new and other old at normal low power usage i do not think its enough of a difference to trip the fuseLet's say only one fuse trips. What happens next? I guess the "faulty" battery will be replaced by a new one. If so, it's likely that it is not charged to the same level as all the other ones. And - because of fresh - the internal resistance may be lower than at the old ones. Which means the current (either charging or discharging) may be much higher than with the old ones. --> overcurrent --> fuse trips at the most healthy battery --> total system fail.
yes the system is overdimmentioned just to make it last long and keep it allive for longer, if a fuse trip i could remove one fuse from the other paralell banks as well to rebalance the system with less batteries at work.In my opinion the idea should be to keep the sytem alive as long as possible.
Usually weak batteries (connected in parallel) draw the lowest current (unless a battery internal short circuit happens. But how likely is this?) So the fuse at the weak battery will not drop.
thats a good pointThere is a good reason for "true health check circuits" on paralleled batteries.
inverter
I agree.The frequent advice here is it's more practical to string batteries in series rather than parallel.
An RS flip-flop can respond to a momentary voltage change, and latch. It's a memory cell. You can make it from a logic gate with hysteresis feedback if you adjust resistor values properly. Connect all inputs of a gate having more than one input. If you use invert-gates, assemble two invert-gates to create one memory cell.
View attachment 185423
A potentiometer (or resistor divider) might do the job. Or zener diode and potentiometer in series. Substitute a string of diodes/led's for the zener diode.possible to set treshold value / adjust sensitivity?
tanks for your reply. isnt this overcomplicated? in my case the fuse is mainly protecting internat short circuit it wil newer blow from over carge/discharge current as there are more fuses down the lineYour biggest problem is to define all the assumptions for this design to work.
This has not been done yet. Once this is done, the design is easy.
Current exceeding fuse rating ( excess voltage) may not be a reliable indicator since fuses can take a long time when operating near the threshold. What you want to know is, I think, is the battery drawing current from an internal short when it should be supplying current. Another possible feature is detecting a failed cell that is degrading the pack from low current due to high ESR and possible low C. The most critical test for repacking cells in a used pack is matching the ESR when all are charged to the same voltage. Having a cell ESR, Capacity tester is a key tool to have which pulses current and measures dV/dt for charge/discharge.
Fuses have thermal runaway above a certain temperature at a constant current. They are rated in I^2*t and Rs for room temp or simply the holding current. This translates to a voltage drop near 100 mV but is bipolar with charging and discharging. In order to detect both conditions a precision rectifier is needed. Precision comparators are required to detect above this threshold in order to reach a latched threshold. After the fuse is blown its voltage drop depends on how much the no-load battery voltage returns compared to the parallel string voltage. One can model a battery with a Cap, 10kF for 16850 and some ESR then another RC pair for the long-term soak charge values.
In parallel cells, the battery with the lowest ESR draws or supplies the most current unless there is an internal partial short which is undetectable by voltage but perhaps an array of thermal sensors or measuring each fuse voltage drop for relative changes.
Dendrites can form when the cell is with excess current and may be bigger than the fuse, which at least blows it from the pack. Dendrites can also form at very low lower SOC but tend to be smaller than the fuse rating so heating occurs and can age a cell more rapidly when V drops well below the others in series and takes out the other paired cell too. Pulse charging can mitigate this.
Although current sensors tend to be unipolar only unless there is a differential output.
I think a smart monitor with a uC would be best for BMS and fuse detection.
Recommendation.
One reliable way to detect an open circuit is to drive a constant current and measure voltage like any RLC meter. It could be DC or AC or a multiplexed pulse to scan all fuses.
These fuses being on the outside of every series rail may cause a design requirement to create an extra supply voltage outside the V+,V- rails to power for those designs that are simply voltage sensors with latches.
If anyone wants to try a design on a simple battery pack , I created a model here. I had previously chosen 14A fuses which will eventually blow from a Reset charge voltage and CC setting just more than 15A.
https://tinyurl.com/yvjfnq36 Falstad Simulation
View attachment 185476
Matching the ESR's and battery voltages is critical as these are simple indicators of battery capacity. In parallel packs the strongest cell gets the biggest stress, while in series strings the weakest cells get the most stress. This means a low C battery changes voltage the fastest I=CdV/dt and high ESR are also weak batteries or low SoC.
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The problem with driving the fuse to sense it is that its battery is in parallel with the fuse nodes in the loop so that these nodes are never high impedance.
And here I exactly see the problem.when any voltage difference is detected the circuit latch
I plan to use regular car 12v fuses LinkHi,
And here I exactly see the problem.
On the one hand: a fuse will drop voltage. I mean a standard fuse works as a resistor, with current and voltage drop. Multiply both to get the dissipated heat in the fuse wire. It needs to get hot enough to melt for the fuse to trip.
Without voltage drop (during normal operation) --> no dissipated power --> no heat --> not fuse trip
im more of a "make it adjustable" type of guy but i could connect a scope across the fuse and have a look when i pull 25A and disconnect the fuse,On the other hand: the system - as already mentioned - does not guarantee a meaningful voltage drop to detect a broken fuse. At leat you gave no numbers.
So we need to guess
* the used fuse with all it´s specifications
* the allowed currents on each path
* the "allowed drop" of a non tripped fuse
* the guaranteed drop on a broken fuse.
* and so on
We don´t know the specifications and functions of your system. If you don´t provide them, how can we know?
a reset push button on the circuitboard itself would be greatYou even did never answer how you decide to "reset" the latch.
yes i wil return to it when i test with scope*******
So for me a useful concept could be:
* monitor the voltage across the fuse
* and monitor the current through the fuse
* and get three states:
1) fuse good
2) fuse state not determinable (on too low voltage drop)
3) broken fuse
And you - yes you - need to give the values (numbers and units) of voltage and current thresholds for
* good state
* broken state
And you need to give informations abotu the expected function.
Diagrams, tables, sketches, flow charts ... may be more helpful than a lot of vague text.
Klaus
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