BJT diode connected load

Status
Not open for further replies.

sarge

Full Member level 3
Joined
Dec 29, 2009
Messages
187
Helped
57
Reputation
114
Reaction score
56
Trophy points
1,308
Visit site
Activity points
2,170
Hi, i'm trying to calculate small signal gain for common emitter amplifier with bjt diode connection load.
For diode connected bjt resistance is equal to parallel connection of Rbe and current source b*Ib. Rbe much smaller then Rcs and therefore Requal ~ Rbe.
For gain we have A = -gm1*Rbe2

Am i right?

Update: Sorry, i said stupid thing, resistance of diode connected load is the Re. But anywhere i still can't calculate small signal gain. Re = Vt/I = 1/gm - same as in mos device. A = gm1/gm2 = (I/Vt)/(I/Vt=1 ^(
Where did i made mistake?
 
Last edited:

Status
Not open for further replies.
Cookies are required to use this site. You must accept them to continue using the site. Learn more…