Hello FvM,
thanks for your interest in my problem.
I'll provide more details:
In normal operation, I need to measure the current (1-10A) in some circuit.
Therefore, my switch is normally closed and the shunt resistor (10mOhm) is right next to it.
It is necessary that voltage drop on the switch and the shunt (when I=10A) is <= 1V.
That means that switch resistance must be <= 90mOhm.
Now the problematic part:
The rest of the circuit is problematic and that's just the way it is, and no changes can be done on this matter.
It can happen that sometimes (by an accident) 1000V can appear between switch contacts (actually, switch + shunt).
This condition must be quickly detected and the switch must be turned off immediately.
I'll have one fuse next to the switch. Actually, accident situation, mentioned above, can happen frequently.
Fuse is too slow, and even if it would be fast enough, changing fuses frequently is not an option.
By project specification, measurement circuit should recover fast from this accident and to be able when needed to start
measuring current again.
This is not an easy problem, possibly it is not feasible at all.
I need to analyze it, and to have good arguments if I decide to say NO to the customer.
P.S.
Driving a switch is another subject. First, I need to find out what kind of switch to use.
Thanks!