Lets pretend that this amp has the same 80nA bias to both + and - inputs. If the + input has a 10K to ground then offset voltage = 10k X 80nA = 800 micro volts. if the - input has 100K to ground then its offset voltage = 8mV. Now if the gain of the amp is > 100, then the output voltage will be (-8mV + .8 mV) X 100 = -.72V. So if it is important for the output to be at 0 DC in the absence of a signal, or the gain is higher then 100 or so, the input bias currents must be catered for and that must be checked right across the working temperature range of the device.
Frank