The noise power is defined as P= kTB, where k is the Boltzmann constant, T is the temperature in Kelvins, and B is the bandwidth in Hz.
For your frequency band of interest, 10...50 MHz B is 40E6 Hz. The noise power generated by a resistor (of any value, say 50 Ohms) is then defined also by ambient temperature, T = ~300 K.
An estimate in dBm is then P = -174 + 10 log B = -174 + 76 = -98 dBm.
To get 2 Watts or 33 dBm (do you handle the decibels?) the amplifier would have more than 130 dB gain.
Such amplifier can be made bu the design of a flat-response wideband amplifier requires an experienced designer. If you are such person, then look into "www.minicircuits.com" and select suitable chips covering your band of interest, also gradually more and more power to get up to 33 dBm (2Watts).
The NoiseCom company builds similar noise amplifiers but going up to 2 W will be costly.
What is the purpose of your project? If it is a jammer, then read the above colleague's answer first.