i took a quick look at one 50F 3V supercap. maximum ESR is about 13 mohm
(i picked the one with the lowest ESR)
RC time constant (for two in series - 25 F and 26 mohm) is 0.65 seconds.
full charge in 5 time constants is 13 is 3.25 seconds
if you pull 9 A out of a 25F cap for 5 seconds dv = I/C dt or 9A*5s/25F = 1.8 V (much bigger that dick_freebirds reasonable 10%)
assuming a constant current
using dick_freebird's analysis:
dt = Cdv/I, dt = 25F 0.6V/9 = 1.7 seconds (assuming 2x50F 3V caps in series)
still not goint to make 5 seconds on
as i read what you wrote:
….Then we simply draw a constant 9A from the battery….for 5 seconds we send the 9A to the one flashlamp from the battery....and the same power to the 2nd flashlamp but from the supercap...then for 5 seconds we charge the supercap with 9A.....?...etc...to be continued...
So basically, we draw constant 9A from the battery.....for 5 secs send it to flashlamp1...then for 5 seconds send 9A to the supercap...........the supercap will augment the light by giving 9A to the flashlamp2...which has the right voltage so that it gives the same power as the flashlamp1, when it flashes.
Does this sound the best way?
charge supercaps
loop start:
power flashlamp 1 from battery, and power flashlamp 2 from supercap for 5 seconds
recharge cap from battery for 5 sec with both flashlamps off
repeat loop
plus losses from switching current path out of batter and to either a flashlamp or capacitor
probably going to draw closer to 10A from the battery
with glitches every time you switch the current