basic Practical Integrator Design

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Tra002

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Hello Everyone,

I'm designing a practical integrator with a low frequency gain of 15db, and a a start of integration range of 1000Hz.

What I first did was set the capacitor value to 10nF, and found R2 using the equation fc=1/(2*pi*R2*C), where I assumed fc=1000Hz.

Now do I solve the R1 value using the simple inverting op amp equation for gain, where gain=-R2/R1? Also was setting the capaitor value to 10nF reasonable?

Thanks!

Ray
 

Depends on your understanding of "start of integration range". If it's meaned as the pole frequency of lossy or "practical" integrator, the calculation would be right,

In other words, you are making a first order low-pass with 1 kHz cut-off frequency and 15 dB gain.
 

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