Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Bandwidth of AM - some explanation please

Status
Not open for further replies.

mehboob_iiui

Full Member level 2
Full Member level 2
Joined
May 20, 2006
Messages
132
Helped
8
Reputation
16
Reaction score
1
Trophy points
1,298
Location
Rawalpindi - Pakistan
Activity points
2,013
Bandwidth of AM

In bandwidth we change the amplitude of a carrrier with respect to a signal, the frequency of the carrier remains constant but its spectrum covers a range of frequencies, why is it so?
 

Bandwidth of AM

In AM we have 3 frequency.
Carrier frequency
Upper side band
lower side band
in the other word we have: Fc, Fc+Fm, Fc-Fm
(Fc=Carrier freq, Fm=message freq.)
 

Bandwidth of AM

I'm Agree with Davood Amerion, but remember that the signal to transmit is baseband and frequency limited, that is from 0 to 4kHz for voice, or 0 to 20kHz for music, etc.

So you can calculate AM DSB from Fc-4kHz to Fc+4kHz for voice.

Fc-20kHz to Fc+20kHz for music.

You can consult the modulation theorem in any book of Fourier.
 

Re: Bandwidth of AM

in AM

we get the components of final modulated signal at fc+fm and fc-fm, so it is seen the carrier frequency actually changes but as

fc >>fm (fc much greater than fm)

we assumes that carrier frequency fc does not change.
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top