bianchi77
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I made :
The code above is already displaying the voltage on ADC pin, am I right ?
Then,
What's the calculation, so the display on LCD is equal to "Input voltage" ?
Currently I used 56K : 10K resistor voltage divider.
Thanks
- - - Updated - - -
thanks
- - - Updated - - -
is it this one ?
Code:
int adc_result;
double adcA,d,adcresistance;
char voltage[50];
adcA = ((int)(5000/1023)*adc_result);
lcd_xy(0,0);
lcd_string("Voltage:");
if (adcA != 0)
{
sprintf(voltage,"%.2f",adcA);
lcd_xy(1,0);
lcd_string(voltage);lcd_string(" mV");
}The code above is already displaying the voltage on ADC pin, am I right ?
Then,
What's the calculation, so the display on LCD is equal to "Input voltage" ?
Currently I used 56K : 10K resistor voltage divider.
Thanks
- - - Updated - - -
What's the calculation for displaying voltage input on LCD ?
thanks
- - - Updated - - -
is it this one ?
Code:
adc_volt = ((adc_steps*0.00488)*4000)-(((1023-adc_steps)*0.00488)*4000); //Formula for positive