kel8157
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I think you cant do that. Your signal band depends on channel symbol rate but not on sampling rate of your ADC.
When you reduce channel symbol rate twice you get a halfband signal.
To preserve initial data rate you may increase your signal constellation dimension (e.g. 16QAM instead of QPSK) but this requires greate SNR.
Or use an input data compression, but you cant perform a lossless compression on a random bit stream.
Assume that I sample a downconverted/bandlimited RF from ADC, and it contains 5MHz, 8MHz, 9MHz.
Are there any digital operation which can convert them into 2.5MHz, 4MHz and 4.5MHz?
Are there any analog circuit which can do the conversion before ADC?
If you mean 5,8 and 9 are bandwidths - the answer was NOT.
The spectrum and time series are just two sides, two representations of one process.You cant compress or expand the signal in frequency domain without influencing time domain and vice-versa.
For the purpose to reduce sampling rate that you claimed above you may take the band from 5 to 9 MHz, not from 0 to 9 and that will give the reduction of processing speed. For 3-tone signal you cant shift that frequencies the way you wish.
compress the BW means you need to think this in freq domain.
that is you first need to do a fourier transform, x(t) -> X(jw)
now you will have a X(jw), now you want half of the bandwidth of this thing. That means you want to compress the w by a factor of 2, this can be done by downsampling in freq domain by 2. In such way, you will obtain a uniformly modified signal. Then you can inverst FT to get the signal in time domain, say x'(t).
You do not need to shift the freq in this situation, since since after all you will inverst FT it.
Just provide the band of interest to fit the nyquist zone (any, not the 1st exactly) and provide an analog antialiasing filter at ADC input
i am not sure whether we can do anolog downsampling thing, usually we have to do this in digital field. Like first ADC it, and then DAC back.
The reason behind this I think is that anolog is more like time domain thing, thus to build a anolog circuit for the purpose of downsampling seems not reasonable.
Obviously all digital circuits built from analog, thus finally I think we can still say it is a analog circuit. However, it is not the pure analog, which means discrete value for voltage but not quantized ones.
In such way, there is really not meaningful to build such "analog" circuit. It is reconmended you buy the ADC and DAC, or even a PIC to do such job.
I am not sure whether my statement make any sense here. Yet hope it could help a bit.
I'm not sure that I understood a single word from your post, sorry.
Sampling is a digitizing process. After sampling there is a digital domain. And antialiasing fiter at the ADC input is always analog.
If kel8157 has a strong wish to reduce sample rate he can do it by narrowing the band of interest (by the way this leads to the adequate losses in SNR (i.e. processing gain)).
For example having the upper tone of 9 MHz one should sample at 18 MHz at least (even more in practice). But for a set of known frequencies of 5,7 and 9 MHz - they all get into 2nd nyquist zone for 9.5 MHz sample rate (band from 4.75 to 9.5). This is the sample rate reduction - this three tone signal may be sampled at 9.5 instead of 18.
And supplementing this clarificationAssume that I sample a downconverted/bandlimited RF from ADC, and it contains 5MHz, 8MHz, 9MHz.
Assume there are 3 tones of that frequency.
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