analyze and find oscillating frequency

I like Diodes Inc version of the triangle generator more for the ‘358 and others. RRIO are preferred.

hi
I discussed the matter of impedance calculation in #28
can anyone guide me on how to calculate(or measure) the impedance?

KlausST said:

Hi,

The thread currently has more than 1k views. Every single member who wants to helo needs to do the search for the datasheet.
Do yourself a favour and post a link to the datasheet directly at the manufacturer site.
1x your effort vs 1000x the helpers effort and the risk to talk about different surces of informations.

Klaus

Click to expand...

hi
i read:
https://www.onsemi.com/download/data-sheet/pdf/lm358-d.pdf

Most easily, you look at the basic inverting amplifier configuration with two resistors. If you assume ideal OP, no calculation is necessary because you can consider the inverting input as virtual short.

Hi,

akbarza said:

I discussed the matter of impedance calculation in #28
can anyone guide me on how to calculate(or measure) the impedance?

Click to expand...

Impedance of left side of the 1M.

there is this 100k resistor. It domonated the total impedance.
One can be sure that toatl impedance is below 100k.

If you want to die deeper then caclualte the impedance of the connected capacitor:
With the well known formula: Xc = 1 / (2 * Pi * f * c)
since it´s in series with the signal ... the true "source" impedance through the 1n capacitor is a bit higher.

Without complicated calculations I expect all three RCs to generate 180° phase shift. (needed for oscillation) So each single RC about 60°.
For 60° phase shift Xc needs to be about twice of R.
So I expect the Xc of the 1nF to be about 2*100k = 200k.

To calculate the total impedance of 100k (R) and 200k (Xc) you have to use Xt = 1 / (1/R + 1/Xc) = about 66k.

This all is just done without caclulator, just to give a feed about what to expect. Nothing precise.

***

If you want to do it more precisely I recommend to calculate the impedance beginning
* from the OPAMP´s output (considered to be close to 0 Ohms) --> 100n --> 10n --> 1n --> 1M for sure including all Rs.

Klaus

Input Z calculation, see attached. Degenerate the stage to simple Inverting amp, NI input grounded.

A sim :




Regards, Dana.

Not sure what "Impedance @ R1" is in your simulation. Original question:

akbarza said:

I want to know the impedance seen from the left of the 1M-ohm resistor, what can I do? must I break the connection of opamp's output and 100n cap? or it is not necessary?

Click to expand...

In my understanding this doesn't refer to a node impedance but to load impedance generated by R1 + inverting input impedance (effectively 0 in the frequency range of interest).

Background of the question is, as I think, calculation of phase shift network load.

I thought it was 100K ohm in original post.

I have an inconsistency in the simulator and am trying to get answer, stay tuned.


Regards, Dana.

Hi,

FvM said:

Not sure what "Impedance @ R1" is in your simulation. Original question:

Click to expand...

One question - many possible answers.

In post I thought the OP was asking for the source impedance ... provided to the 1M resistor ..

I´m not sure now whether this is what the OP was asking for.

Klaus

I had an error in post #45, in way Z probe in sim was used. Below corrected. But I am suspicious
of sim because internal comp pole seems to occur not at 10 Hz but at .1 Hz, two decades earlier.
So I did a plot w/o integrating cap, 100 G ohm fdbk R, and it does show open loop pole at ~10Hz.





Regards, Dana.