boylesg
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The output of a 555 sounds like a buzzer. Is that what you want?
Can you point me in the direction of an example circuit?It will work, subject to the limitations Dan has already mentioned, and the 'buzz' can be shifted out of audible range by speeding up the oscillator but it isn't really a good PWM generator as the control input on the second 555 has limited range and linearity. I suggest using a dual op-amp instead, one half generating a triangle wave and the other working as a comparator against the incoming audio. It should give far better results and probably in fewer components. You might need a little more current gain at the output so the op-amp can drive the power transistor.
With a further inverter stage (using a quad op-amp maybe) you can easily make a bridge output stage which gives four times the output power and removes the residual DC from the loudspeaker.
Brian.
Thanks Brian. I think I just might have a fiddle with this just for the satisfaction but I will still probably implement the circuit with 555s because I have a heap of them.There is an excellent description here: www.ti.com/lit/ug/slau508/slau508.pdf
It is obviously promoting TI components but the principle is the same if you use alternative devices.
To make it a bridge circuit you need to drive both ends of the loudspeaker with opposite polarity PWM signal (one side inverted) so you get twice the voltage and hence four times the power. Ideally you add filtering to remove the PWM switching freqency and only leave the 'average' of the waveform behind but for experimental purposes you could rely on the loudspeaker being completely unresponsive at high frequencies (use > 50KHz).
Brian.
Brian I can see they have given a calculated example of this circuit but I can't see where they have specified what the supply voltage should be for their calculated component values.There is an excellent description here: www.ti.com/lit/ug/slau508/slau508.pdf
It is obviously promoting TI components but the principle is the same if you use alternative devices.
To make it a bridge circuit you need to drive both ends of the loudspeaker with opposite polarity PWM signal (one side inverted) so you get twice the voltage and hence four times the power. Ideally you add filtering to remove the PWM switching freqency and only leave the 'average' of the waveform behind but for experimental purposes you could rely on the loudspeaker being completely unresponsive at high frequencies (use > 50KHz).
Brian.
Brian I can see they have given a calculated example of this circuit but I can't see where they have specified what the supply voltage should be for their calculated component values.