Re: Looking for an on/off digital toggle signal chip
Hey Brian!
Thanks for your reply!
I will try to make a block diagram of the system, in the meantime, i have several questions:
I would have used the Arduino sleep library - but the problem/advantage is that i have separated the servos power line from the Arduino - the servos get the voltage directly form another LiPo via a small regulator - for the sake of a better power distribution and also not to damage ultra-sound sensors reading that i have on the Arduino - it seems that when the sensors and the servos are connected both to the Arduino 5V output, every time the servos start working the sensors go buzzerk. As well, it seems to me in general that the Arduino can not let out enough current for the servos.
Basically what i did and maybe it was an error - is that i have purchased this relay:
**broken link removed**
Now, regarding this above relay i have a question:
I have this regulator:
**broken link removed**
If i have on one side of this regulator (input voltage) the Arduino Uno 5V 40mAh digital pin (PWM) output - Can i get on the output voltage side of this regulator, the 18V 9mAh input voltage logic signal needed for the above relay?
And i have another question:
I was discouraged to use a chip of the following characters:
https://pdf1.alldatasheet.com/datasheet-pdf/view/26882/TI/CD4066.html
That basically, it seems to me, on the logic and analog side, can act just like the relay i mentioned above - But on the data sheet there is this detail:
"DC input current, IIN (any one input) . . . . . . . . . . . . . . ±10 mA"
So, although for a newbie inexperienced electronics hobbyist like me, the common knowledge is that current is something that is drawn by the end device and not "pushed" forward like voltage - i was still concerned that if i put through the analog legs of this chip, the LiPo 2-3S 2000 mAh current, while it specifically says that the DC input current is 10 mAh - then i might damage the chip. Or is it, as mentioned above by you, i will not damage the chip - it is just that the chip will not be able to give out on the other side a big enough needed current?
Was that concern justified - or have i just made an error, while moving from the relatively inexpensive chips playground to the more pricy relays playground?
Thanks a lot,
I hope i make any sense with my questions.
Roi.