Oct 4, 2013 #1 S sadhana bodavula Newbie level 1 Joined Oct 4, 2013 Messages 1 Helped 0 Reputation 0 Reaction score 0 Trophy points 1 Activity points 6 A periodic signal is given by X(t)=3sin(4t+30)-4cos(12t-60) then what is the amplitude of second harmonic of X(t)?
A periodic signal is given by X(t)=3sin(4t+30)-4cos(12t-60) then what is the amplitude of second harmonic of X(t)?
Oct 5, 2013 #2 K Kalyan_Acharjya Newbie level 4 Joined Sep 20, 2013 Messages 5 Helped 0 Reputation 0 Reaction score 0 Trophy points 1 Location Jaipur Activity points 24 This is your X(t), check the result. Any Question ??? Last edited by a moderator: Oct 5, 2013
Oct 5, 2013 #3 A albbg Advanced Member level 4 Joined Nov 7, 2009 Messages 1,316 Helped 448 Reputation 898 Reaction score 409 Trophy points 1,363 Location Italy Activity points 10,049 Your signal is made by only two angular frequencies: 4 and 12 rad/sec, that is fundamental and third harmonics (4x3=12), no matter the two phases (30 and -60 rad). No second harmonic is in it. Kalyan_Acharjya said: This is your X(t), check the result. Any Question ??? Click to expand... To check the harmonics content the time domain representation is useless; the frequency domain (FFT) representation have to be used.
Your signal is made by only two angular frequencies: 4 and 12 rad/sec, that is fundamental and third harmonics (4x3=12), no matter the two phases (30 and -60 rad). No second harmonic is in it. Kalyan_Acharjya said: This is your X(t), check the result. Any Question ??? Click to expand... To check the harmonics content the time domain representation is useless; the frequency domain (FFT) representation have to be used.