ADS : How to simulate frequency dependent resistor (and inductance)
Cc everyone
Please, I want to know how to simulate a frequency dependent resistor and inductance, the problem is that I don't know how to write the equation of the resistor, and where, here is the equation of my component R, it is for an electrical modeling purpose:
R = sqrt((R_ac)^2 + (R_dc)^2);
and R_ac = a/ ((b*Skin) - (pi*(Skin^2))) ;
R_dc = 5.94e-4
the variable skin that represent the skin effect that occurs to a resistance at high frequency: Skin = 1./sqrt(pi*freq*5.9524e7)
a=1.68e-12 , b = 1.884e-4;
I can't simulate S-parameters because ADS does'nt allows frequency dependent Resistor and inductance, please give me a simple way to solve this problem.
ADS provides a set of equation based elements that can be controlled by functions that are dependant on the simulation frequency.
In this case instead of the ideal resistor use the Z1P_Eqn, a 2 pin device, and set the Z[1,1] parameter to have a real part that is the required frequency dependant resistance value. For a resistor the imaginary part of Z[1,1] is 0 so this does not need to be defined as the default is 0.
You schematic becomes:
and this simulates giving the expected frequency varying resistance.
The Zin plot is calculated as Z[1,1] - 50 to take off the effect of the load resistance and plot the equivalent series resistance of the Z1P_Eqn.
I appreciate your help RealEAL, this is exactly what I need, but I want to know, why did you add "Zin" ? I tried the same schematic without it and it gives the same results
It was just an easy way to see Z[1,1]. You would not see that normally when doing a regular s-parameter simulation. Of course you could write an equation to calculate Z[1,1] from S[1,1] but this measurement item does if for you. It does not change the results for the resistor. Just an extra measurement.
I could have done something similar by simply plotting the value of the variable Rtgv but that would be only the resistor value only and not the equivalent series resistance of the entire circuit. Almost the same but not quite: