Hello , on the third minute of the manual shown in the link at minute 3 he says that when we add a resistor our added pole is 1/(Rop+Radd)C
Then he says that when the impedance of the capacitor in the same order ar the added resistor then we have a ZERO effect and the slope gets less steep.
How does a pole can turn to zero?
What is the math behind it?
Thanks.
When Impedance of C matches series Rs then you are near critical damping.
My RLC impedance 4D graph helps look up these values.
e.g. here L=C=1e-9 and Zo=sqrt(L/C)= 1 so adding Rs=1 make it "near" critically damped with a very low peak in frequency response and shifted slightly lower. (Q = 1⁄2) is said to be critically damped.
There are tables with direct correlation to 2nd order Q and overshoot.
In physics and engineering, the quality factor or Q factor is a dimensionless parameter that describes how underdamped an oscillator or resonator is. It is defi...