doooo
Newbie level 5
Consider the simple electron energy band schemes for metal.
All frequencies of visible light are absorbed by metals becuase of the continuously available empty electron states, which permit electron transitions.
Then, most of the absorbed radiation is reemitted in the form of visible light of the same wavelength, which appears as reflected light (from excitation state to ground state)
Usually, the reflectivity for most metals is between 0.90 ~ 0.95.
How can I explain that some small fraction of the energy is dissipated as heat?
And why metals have different reflectivity??
Thanks
All frequencies of visible light are absorbed by metals becuase of the continuously available empty electron states, which permit electron transitions.
Then, most of the absorbed radiation is reemitted in the form of visible light of the same wavelength, which appears as reflected light (from excitation state to ground state)
Usually, the reflectivity for most metals is between 0.90 ~ 0.95.
How can I explain that some small fraction of the energy is dissipated as heat?
And why metals have different reflectivity??
Thanks
