Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.
what is the output for the circuit attached here?any explain it pls.....what is the fun of the diode as feedback to the voltage regulator?what should be happening regulator is connected to ground via diode?explain it pl
ss..
That diode is in backwards(the one across the regulator). Your output voltage will be Vin-Vdiode, the regulator does nothing, the other diode does nothing..
If you reverse the polarity of the diode across the regulator it has the function to protect the regulator itself against the reverse current. If that diode is not present, the output capacitor could discharge through the regulator, so that the current will flows from the output towards the input of the regulator an can damage it. Usually this protection isn't really needed since the Vout-Vin is no high enough to damage the component since the capacitor will start to discharge toward the load.
I noticed that you supply the regulator by means an AC generator. I suppose it's a DC generator with superimposed a sinwave simulating the ripple in output of a Graetz bridge.
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.