About the equation ni^2=n0p0

[qiushidaren]

n x p=ni

In Trividis’s book, he says that “With so many free electronics moving around the lattice, the chance of their encountering a hole in their way and filling it, or ‘recombining’ with it, is significant; thus the concentration of holes denoted by p0 decreases compared to that in the intrinsic case. In fact, this chance of recombination is approximately proportional to n0, and thus p0 decreases by the same factor that n0 has increased (compared to the intrinsic case). Hence, the product n0p0 remains the same as in the intrinsic case, …”

I just can't understand these sentences perfectly--In fact, this chance of recombination is approximately proportional to n0, and thus p0 decreases by the same factor that n0 has increased (compared to the intrinsic case). Hence, the product n0p0 remains the same as in the intrinsic case, …
Can someone explain these sentences more intuitive for me to understand, thank you in advance!!!

 

[aomeen]

Hello,

One of the semiconductor basic equations is nxp=ni²... this equation is true for both intrinsic and extrinsic case. this means that for n-type semiconductors, if n is increased by factor of 100, p will also decrease by facor of 100, i.e n=100no and p=po/100 where no and po are intrinsic n and p concentrations, such that nxp is still ni².

 

[qiushidaren]

Hello,

One of the semiconductor basic equations is nxp=ni²... this equation is true for both intrinsic and extrinsic case. this means that for n-type semiconductors, if n is increased by factor of 100, p will also decrease by facor of 100, i.e n=100no and p=po/100 where no and po are intrinsic n and p concentrations, such that nxp is still ni².

Thank you, I get it!

 

[FCMOS]

An intrinsic semiconductor np=ni

An extrinsic semiconductor is n*p=ni^2

Regards