I want to design a 12bit current dac. therefore I need a reference current source.
I already have a quite precise reference voltage of a bandgap with less than 1% variation on chip.
How can I generate a reference current with the same accuracy?
The poly resistors in my process are quite bad.
Thus I wondered if it is possible to mirror the current directly out off the bandgab circuit.
When would I need to buffer this dac reference current and how is this normally done?
Generate current sources using this band gap. Various methods like Voltage followers , B-multipliers are available. Generally Bandgaps are preferred not to be loaded.
Hello scoobydoo,
If you mirror the current from the BGR, this current will be I = delta_VGS/R, am I right? So it will continue to be dependent on the resistor tolerance (some times, 20%).
If you can trimming the generated current, your work can be easier.
It may be better if you use a current source that does not use resistors. (I have never designed 12bit current dac).
Regards,
I'm sorry....I think I was not clear. I didnt say that you reference is not precise. But there is significant difference betweeen the output voltage and the current.
The output voltage can be very precise, but I'm not sure about the current. Do you agree?
this current depends on directly the value of the resistor....do you agree? So... it seems that it does not varies less than 1%. If yes, your resistor varies less than 1%. Is it true?
There are some examples of current sources that do not use resistors. I would use one of them.
i just have one question left. assume that there is a current reference as shown by erikl in fig. 8.8 b). is there a problem to connect let´s say 30 currentmirror transistors in the same way as M5 to distribute the current all over the chip?
i read that bandgaps and reference circuits should be buffered because they cannot drive any load.
do i need any kind of current buffering there?
Not at all -- from a dc point of view, because this is a voltage (Vgs) control method, and there's practically no dc gate input current loss.
If the 30 (or so) gates' connection is rather long, however, there's the danger of EM stray pick-up, so you should perhaps add one or more capacitor(s) between this gates' connection and ground (or VDD) to filter such noise.
No. As mentioned above, the constant current(s) are controlled by a constant Vgs voltage, which, on its part, is already buffered by the M4 "diode" connection, whereat the gate inputs don't constitute any dc load.