AB+CD using Half Adder

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You need to use only one AND gate in order to get the ANDing process.
Using D'Morgan's theorem one gets
(~A + ~B).(~C + ~D)
You need the AND gate to AND the 2 brackets.
 

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    kumar_eee

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I'm sorry you can do it all with H-Adders only, and here is your expression:
F = [~(~A+~B)]+[~(~C+~D)]
 

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    kumar_eee

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