Mar 18, 2010 #1 Fractional-N Full Member level 1 Joined Oct 15, 2007 Messages 97 Helped 2 Reputation 4 Reaction score 2 Trophy points 1,288 Activity points 2,071 it is said that "If the reference is jitter free, then the jitter between the reference and the output of the delay line will just be the period jitter." can anyone explain to me why? thanks
it is said that "If the reference is jitter free, then the jitter between the reference and the output of the delay line will just be the period jitter." can anyone explain to me why? thanks
Mar 18, 2010 #2 B biff44 Advanced Member level 6 Joined Dec 24, 2004 Messages 5,059 Helped 1,376 Reputation 2,748 Reaction score 1,060 Trophy points 1,393 Location New England, USA Activity points 37,988 Since we are not on the Planet Zoltar, where signal sources are available that are "jitter free", I do not know what that statement means!
Since we are not on the Planet Zoltar, where signal sources are available that are "jitter free", I do not know what that statement means!
Mar 18, 2010 #3 J JoannesPaulus Advanced Member level 3 Joined Mar 19, 2008 Messages 773 Helped 235 Reputation 470 Reaction score 138 Trophy points 1,323 Location USA Activity points 5,006 I believe you can think of the delay line as a series of buffers with no memory (i.e. loops), therefore jitter affects only the length of each period.
I believe you can think of the delay line as a series of buffers with no memory (i.e. loops), therefore jitter affects only the length of each period.