bagel520
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Dear all,
Here is a question about noise figure. Assuming a three stage cascade amplifier system. Every stage has the same gain and noise figure characteristic(gain=10 dB, NF=10 dB).
Input conditions are: Si= -100 dBm Ni= -174 dBm.
We can calculate the output signal and noise level of each stage based on the SNR definition. The following are the output condition of each stage:
So1= -90 dBm
No1= -154 dBm
S02= -80 dBm
No2= -143.1 dBm
So3= -70 dBm
No3= -133.01 dBm
Let us focus on the second stage. Base on the definition of noise figure, it can be calculated as NF2= So1/No1/So2/No2= 64/63.1= 0.9dB.
Why the answer is 0.9 dB? Not 10 dB? I know the second stage's noise figure won't be 10 dB because of the first stage's gain[(10-1)/10]. But it's the mathmatical way. What happened in the physical or electrical point of view?
Here is a question about noise figure. Assuming a three stage cascade amplifier system. Every stage has the same gain and noise figure characteristic(gain=10 dB, NF=10 dB).
Input conditions are: Si= -100 dBm Ni= -174 dBm.
We can calculate the output signal and noise level of each stage based on the SNR definition. The following are the output condition of each stage:
So1= -90 dBm
No1= -154 dBm
S02= -80 dBm
No2= -143.1 dBm
So3= -70 dBm
No3= -133.01 dBm
Let us focus on the second stage. Base on the definition of noise figure, it can be calculated as NF2= So1/No1/So2/No2= 64/63.1= 0.9dB.
Why the answer is 0.9 dB? Not 10 dB? I know the second stage's noise figure won't be 10 dB because of the first stage's gain[(10-1)/10]. But it's the mathmatical way. What happened in the physical or electrical point of view?