[SOLVED] A problem in Razavi CMOS Book

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HAIDE

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In this picture shown a circuit how it find vin(min) and vin(max)
**broken link removed**
 
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Hello Dear HAIDE
The attachment isn't available.
Can you draw it , please ?
Best Wishes
Goldsmith
 

For M1 to be in saturation :

VDS1≧VDS1,sat=>
VD1-VS1≧(VGS1-Vth1)=>
VD1-(Vin-VGS1)≧VGS1-Vth1=>
Vin≦VD1+Vth1=>
Vin≦VGS3+VDD+Vth1=>
Vin≦VGS3-Vth3+Vth3+VDD+Vth1=>
Vin≦-0.3-0.7+3+0.7=>
Vin≦2.7V => Vin,max=2.7V

Similarly work with M1 and the ISS tail current source (after substituting it with nmos transistor with the given properties) and equation VDS≧VDS,sat to derive the other Vin limit.
 
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    HAIDE

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Not to give you the answer outright but some hints.
1. In the ICMR, all the MOS must be in saturation.
2. For a MOS to operate in saturation, vds>=Voverdrive.
3. Vgs=Vth+Voverdrive
4. Replace the tail current with a NMOS operating in saturation.

Have fun!
 
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    HAIDE

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thank you checkmate & jimito13
 

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