8v sinusoidal to 5v square TTL

[RodSTAR]

Hello people,

I need to convert a sinusoidal signal (0 to 8v range) to square signal (5v TTL), using half voltaje (50%) as "change point" (if >= 4v then: 5v TTL logic high; else: 5v TTL logic low)

To me this is chinese as I am a software guy, but i suspect a LM chip and some black magic may do the conversion.

Any directives or schematic to achieve this goal?

Thanks,
Rod

 

[IanP]

Hello people,

I need to convert a sinusoidal signal (0 to 8v range) to square signal (5v TTL), using half voltaje (50%) as "change point" (if >= 4v then: 5v TTL logic high; else: 5v TTL logic low)

To me this is chinese as I am a software guy, but i suspect a LM chip and some black magic may do the conversion.

Any directives or schematic to achieve this goal?

Thanks,
Rod

The simplest solution would be to feed the signal through a resistor to a 5V Zener diode, as shown on the attached pictures ..
https://www.electronics-tutorials.ws/diode/diode_7.html

:wink:
IanP

 

[jeffrey samuel]

A mos trigger circuit can also be used here the input sinusoid is given at the gate

A voltage of 5 V dc in the source and the output is got as a square wave in the drain resistance of 5V

 

[pedroromanvr]

You can also use a comparator.
This will work for your case.