DEV123
Member level 2
Hi friends,
Generally any opcode for 8088/86 is having a 6 bit field in instruction format. But 6 bits corresponds to 2^6 = 64 combinations and only max 64 instructions are possible. But already there are 117 instructions for 8086. How is it possible?
Can Anyone explain?
-Devanand T
Generally any opcode for 8088/86 is having a 6 bit field in instruction format. But 6 bits corresponds to 2^6 = 64 combinations and only max 64 instructions are possible. But already there are 117 instructions for 8086. How is it possible?
Can Anyone explain?
-Devanand T