Hi have a look at the following link **broken link removed**
Also you can use a 250 Ohm resistor in series at the current output, and the drop voltage on the resistor oscillates to 1-5Volts. You can convert the 1 Volt to 0 by using comparator.
What you have is "inverterting" configuration on non-inverting input and similar, but opposite story on the non-inverting input ..
If you connect 4-20mA to R5 (not R4) and R5/R6 to pin 3 (+), and R4 to R2/R3, and the other side of R4/R7 to pin 2 (-), you will have 0-4V for 4-20mA ..
Next, you need the gain of the second opamp of 1.25 (already there) and this should produce the output of 0-5V ..
I am very sorry guys for the wrong schematic that i have already uploaded. I made the mistake by momentum.
The mistake is on the first amplifier.The whole circuit works as follows. The R1 converts the 4-20 mA to 1-5 Volts. The first amplifier works as subtracter. It substracts 1Volt (by the voltage divider of R3 and R2 for 10V power supply) from the range 1-5 Volts. So the voltage range after the subtraction is 0-4Volts. Next the voltage is amplified with 1.25 gain, and finally we have the desirasble range.
I will upload the new schematic.
Regands
pls check the image:the sensor provide a 4-20mA signal to that module,you connect 12V power supply between PIN"4" and Pin"5",and PIN"8",PIN"9"can have 0-5V output.
pls check the image:the sensor provide a 4-20mA signal to that module,you connect 12V power supply between PIN"4" and Pin"5",and PIN"8",PIN"9"can have 0-5V output.
pls check the image:the sensor provide a 4-20mA signal to that module,you connect 12V power supply between PIN"4" and Pin"5",and PIN"8",PIN"9"can have 0-5V output.