area of secondary conductor when high current -Inverter Transformer

[thannara123]

As I get the web search
The area of the primary or secondary Conductor measured as
= The current in the conductor / Current density of copper (ie,2.3)
if current is .23A
The area of the conductor = .23A/2.3A mm^-2 = 0.1mm^2 = selected wire is 27AWG
The my question is whenever the current is above 100 Ampere how to select the copper .?
because of for example Current = 100Amp
Area of conductor = 100/2.3 = 43.47mm^2 AWG 1 require it cannot wind what is option ?

 

[CataM]

Such high current which cannot use your 1 AWG solid wire because of skin effect needs Litz wire on its winding.

 

[FvM]

More information needed. What's the operation frequency?

 

[thannara123]

Operation frequency is 50 Hertz

 

[FvM]

Copper skin depth at 50 Hz is 9 mm, there's no noticeable skin effect for a 40 mm² massive conductor.

Suggest to review the design of industrial transformers to learn about winding options. The simplest way for DIY is using multiple wires in parallel.