Audioguru
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Indeed, that's absolutely necessary for 500W. A threefold darlington circuit reduces efficiency with 12V supply, unfortunately. But it's an effective way to deal with unknown 2N3055 current gains.4 pairs of 2N3055 transistors
They are rated fot 1/4W. They have a max voltage of 3V across them for half the time so their max average dissipation is only 90mW.maijaz99 said:Thanks Audioguru but Ronnei missed power rating of 100 ohm resistor.
The minimum input resistance of the opamp is about 1M so a resistor value from a dead short to about 100k will work fine. The circuit used 4.7k resistors.and the values of resistors at pin 10 and 11 of CD4047.
A 10v transformer makes a rectified and filtered 12.3V which is too low to charge a 12v lead-acid battery. 13.8vDC is needed.Another point is the transformer is 10V-0V-10V rating that can be used for step up OK but if u need to use the same for 12V battery charging, its simply unpedictable.
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