180 degrees phase shift in CE amplifier

Status
Not open for further replies.

purnapragna

Advanced Member level 4
Joined
Oct 21, 2005
Messages
107
Helped
6
Reputation
14
Reaction score
3
Trophy points
1,298
Visit site
Activity points
2,287
hi i have adoubt like how is there is a phase shift of \[180^{\0}\] in CE amplifier output?

can anybody explain it using base-width modulation process?

thnx

purna!
 
Last edited by a moderator:

purnapragna,
Are you referring to a true phase shift, as opposed the the normal inversion that is inherent in the CE topology?
Regards,
Kral
 

I am assuming that you are referring to small-signal ac gain ...

Note that the collector voltage is vc = Vcc - ic Rc. Since Vcc is constant it is considered "ground" for ac signals therefore the voltage at the collector is vc= -Rc ic. Now consider that fact that the collector current is beta (also denoted as hfe) times the base current (ic = hfe ib) and the fact that the base current is proportional to the base (input) voltage. All this means is that the collector current will be directly proportional to the base voltage and will be in phase with the collector current. The collector voltage on the other hand will be 180 degrees out of phase since vc = -Rc ic (because of the negative sign). Is this confusing enough?

If you look at the equivalent circuits for the CE amplifier you will see why this is happening.

**broken link removed**
**broken link removed**

Best regards,
v_c
 

Actually i know this but question asked was how do u explain this phenomenon on the basis of base-width modulation.

thnx

purna!
 

OK take a look here **broken link removed**
and read the discussion in Section 5.4.2 and it may help you with your stuff.
I think base width modulation is also referred to as the Early effect?

check

From http://gabevee.tripod.com/sstubmic.html
[/quote]
 

Status
Not open for further replies.
Cookies are required to use this site. You must accept them to continue using the site. Learn more…