ridgemao1983
Junior Member level 1
A lot of books say, high-speed signals tend to return directly underneath the signal trace on the ground plane.
But I don't understand that, when a high-speed signal travels from the driver to the load, then its return current comes back to the driver on the GND plane, how does the return current flow through the driver to form a closed current loop?
It is easy to understand that if the driver is a battery, the return current can flow through the negative pin to the positive pin of the battery.
But if the driver is an IC's pin, how to form a closed current loop? Does the return current on the GND layer "jump" to its original driver on the signal layer? If it is true, how does it happen?
Thanks.
But I don't understand that, when a high-speed signal travels from the driver to the load, then its return current comes back to the driver on the GND plane, how does the return current flow through the driver to form a closed current loop?
It is easy to understand that if the driver is a battery, the return current can flow through the negative pin to the positive pin of the battery.
But if the driver is an IC's pin, how to form a closed current loop? Does the return current on the GND layer "jump" to its original driver on the signal layer? If it is true, how does it happen?
Thanks.