I have not done the calculation for you. But in general, the length is in the equation in how wide the trace need to be. It is the total resistance of the trace that dissipates the power. The longer the trace, the higher the resistance the trace is IF YOU KEEP THE WIDTH THE SAME. The higher the resistance, the more power the trace dissipates and more it get hot.
Case in point, I designed IC before, the traces inside the IC is in microns width, how can they carry a few amps? This is because they are short. It is not the absolute width that is important, it is the width to length ratio that is important.
To calculate with your example, if both are same thickness......1oz:
1) 2.5cm and 0.3cm width gives 25/3=8.333
2) 1cm and 1.5mm width gives 10/1.5=6.67
The 1cm and 1.5mm width is even better. Hope that helps.
An important note, all these are for DC current or low frequency stuff. If you talk RF, the thickness of copper don't matter as skin effect kicks in, it does not matter you use 1/4, 1/2 or 1oz copper. The current density does not penetrate that deep.